It's just a simple trigonometry problem.

However, the lack of basic data like roller diameters and relative positions of the roller axes prevents me commenting further. ■

Dear Mr. Analysis,

You have shown roller-1, roller-2 and roller-3. It seems that roller-3 and roller-1 are in contact and similarly roller-3 and roller-2 are also in contact. Roller-3 is tending to shift downwards by 25000 N, which is counteracted by roller-1 and roller-2. The roller-3 looks to be drive roller.

These rollers must be part of some useful machine (mechanism) wherein they would be doing some useful work and power consumption. If so, the drive roller-3 will also be applying certain tangential force (torque) to roller-1 and roller-3. The force distribution amongst the rollers will be by combined effect of your stated 25000 N, torque transmission for each roller, roller position geometry, etc.

You may solve the problem by using engineering rules for force and torque transmission. In this regard, some hints are as below.

The practically useful solution is likely to involve engineering work and thereby engineering service. The matter does not appear to be so simple, as it may involve resistances in varied situations, steady state, acceleration state, drive torque, friction grip (?) and its variation etc.

Regards,

Ishwar G Mulani.

Author of Book : Engineering Science and Application Design for Belt Conveyors.

Author of Book : Belt Feeder Design and Hopper Bin Silo

Advisor / Consultant for Bulk Material Handling System & Issues.

Email : parimul@pn2.vsnl.net.in

Tel.: 0091 (0)20 25871916 ■

To me it looks as if -

Roller1 dia. = Roller2 dia.

Roller3 dia < Roller1 dia

Rollers 1, 2 and 3 are all in contact.

But I don't know due to the limitations of the sketch!

Perhaps the "Mechanical Engineering Design engineer" could update his sketch with enhanced information to assist those in this thread who may be able answer his question. ■

20,770 N ??? ■

I used it as a test to give a couple of our young apprentices. ■