Re: Electrical Motor
The formel to use is :
Power = Torque * radial speed
Power = 3 * 0.75 = 2.25 kW = 2250 Watt
Radial speed = 2 *3.141593 *1450 / 60 = 151.8437 rad/sec
Torque = Power/radial speed = 2250/151.8437 = 14.81787 Nm
Problem solved ?
At your service ■
Teus
Electric Motor
Thats all well and good but what is he operating with the motor?, since it is safe to assume he wants a work load against it.
Also in the mix is the start up amperage which is usually one and one half times the rated amperage unless there is a soft start etc.
Also need to know whether it is DC or single or three phase AC, is there a capacitor in the mess some where?
a lot of variables before we can make a recipe. ■
Electric Motor 2
thankz alot man u helped a lot .........when i compared my answer it was the same but the working out was different ..... thankz very much
One Last problem
If the electric motor has a piece of wire of cross sectional 2mm has a resistance of 300ohms. Find:
A)The resistance of the same length and material if the cross sectional area is 5mm
B)The cross sectional of the same length and material if resistance is 750ohms. ■
Re: Electrical Motor
The formal to use is :
R = (rho * L) / A
(rho * L) = A * R = 2 * 300 = 600 Ohm
Then : R = 600 / 5 = 300 Ohm
Then ; A = 600 / 750 = 0.8 mm2
OK ? ■
Teus
Electrical motor
can anyone please help me out with this question....it would mbe much Appreciated thanx
A electrical motor has a efficiency of 75% when running at 1450 rev per minute. Determine the output torque when the power input is 3KW.
can someone help me asp plz ■